Kotare_Hunter 748 Report post Posted August 6, 2015 Its easy to find the winners time but how do you work out the times for the others. If a race in won in 17.20 and the second dog was 1 length in arrears what time did it run ? Is there a calculation that can be used ? Is this calculation the same for all distances ? Showing my lack of knowledge here Quote Share this post Link to post Share on other sites More sharing options...
mmmyb 277 Report post Posted August 6, 2015 I think it's .06 per length Kotare_Hunter 1 Quote Share this post Link to post Share on other sites More sharing options...
modest mouse 469 Report post Posted August 6, 2015 Yep, that's right. Kotare_Hunter 1 Quote Share this post Link to post Share on other sites More sharing options...
Kotare_Hunter 748 Report post Posted August 6, 2015 Thanks Quote Share this post Link to post Share on other sites More sharing options...
lad27 404 Report post Posted August 6, 2015 Ive always gone .7, but close enough Quote Share this post Link to post Share on other sites More sharing options...
Jag1 19 Report post Posted August 6, 2015 There is a calculation in the rules 77.14: .066 of a second shall be the equivalent of one body length of a Greyhound Quote Share this post Link to post Share on other sites More sharing options...
jape again 67 Report post Posted August 7, 2015 That is correct. Quote Share this post Link to post Share on other sites More sharing options...
Kotare_Hunter 748 Report post Posted August 7, 2015 Thanks all Quote Share this post Link to post Share on other sites More sharing options...
